If it's not what You are looking for type in the equation solver your own equation and let us solve it.
^3-K^2-1=0
We add all the numbers together, and all the variables
-1K^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$K=\frac{-b}{2a}=\frac{0}{-2}=0$
| 14+6a=-2a+3 | | 6x-18=4(x-8) | | 2x^2-6x-123=0 | | 10x(8+x)=50 | | 0=-5x^2+7.5x+6 | | 31-5y=6 | | 9+x/6=4 | | 9x-7+15x-5=180 | | 5x/3-x=14 | | z+41/7=9 | | 0=-5x^2+8x+3 | | 5y-8=32. | | 36+u=67(7-u)+u | | x×(126-x)=3393 | | 21-2b=11 | | 3(x=1)-2x=x+3 | | 10-4g=34 | | 4x+x=12*5 | | 2x-48=2 | | y/4+4=7 | | 2x-4x(1+2)=20 | | 12x-9=25-x | | 3–(x–1)=–1–(5–x) | | 12=12y+5y-3y | | 54=z/5+48 | | y=7.50+45 | | 5(2x+1)+7(4x=2)=0 | | a+2/5=-19 | | 4+x(x)=12*5 | | 3(x-5)=22(x-11) | | 4+x(x)=12*(5) | | 25y+12=-13 |